5x^2-20x+27=5

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Solution for 5x^2-20x+27=5 equation:


Simplifying
5x2 + -20x + 27 = 5

Reorder the terms:
27 + -20x + 5x2 = 5

Solving
27 + -20x + 5x2 = 5

Solving for variable 'x'.

Reorder the terms:
27 + -5 + -20x + 5x2 = 5 + -5

Combine like terms: 27 + -5 = 22
22 + -20x + 5x2 = 5 + -5

Combine like terms: 5 + -5 = 0
22 + -20x + 5x2 = 0

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
4.4 + -4x + x2 = 0

Move the constant term to the right:

Add '-4.4' to each side of the equation.
4.4 + -4x + -4.4 + x2 = 0 + -4.4

Reorder the terms:
4.4 + -4.4 + -4x + x2 = 0 + -4.4

Combine like terms: 4.4 + -4.4 = 0.0
0.0 + -4x + x2 = 0 + -4.4
-4x + x2 = 0 + -4.4

Combine like terms: 0 + -4.4 = -4.4
-4x + x2 = -4.4

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -4.4 + 4

Reorder the terms:
4 + -4x + x2 = -4.4 + 4

Combine like terms: -4.4 + 4 = -0.4
4 + -4x + x2 = -0.4

Factor a perfect square on the left side:
(x + -2)(x + -2) = -0.4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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